How do you write $2 x^{4} (4 x^{2} + 3 x + 1)$ $2x^4(4x^2 + 3x + 1)$ in standard form?

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How do you write $2 x^{4} (4 x^{2} + 3 x + 1)$ $2x^4(4x^2 + 3x + 1)$ in standard form?

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Answer 1 · 2017-07-12T21:18:02

See a solution process below:

Explanation:

Multiply each term within the parenthesis by the term outside the parenthesis:

$2 x^{4} (4 x^{2} + 3 x + 1) \Rightarrow$ $color(red)(2x^4)(4x^2 + 3x + 1) =>$

$(2 x^{4} \times 4 x^{2}) + (2 x^{4} \times 3 x) + (2 x^{4} \times 1) \Rightarrow$ $(color(red)(2x^4) xx 4x^2) + (color(red)(2x^4) xx 3x) + (color(red)(2x^4) xx 1) =>$

$8 x^{6} + 6 x^{5} + 2 x^{4}$ $8x^6 + 6x^5 + 2x^4$

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How do you write $2 x^{4} (4 x^{2} + 3 x + 1)$ $2x^4(4x^2 + 3x + 1)$ in standard form?

1 Answer

Explanation:

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How do you write 2x4(4x2+3x+1)2x^4(4x^2 + 3x + 1) in standard form?

1 Answer

Explanation:

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How do you write $2 x^{4} (4 x^{2} + 3 x + 1)$ $2x^4(4x^2 + 3x + 1)$ in standard form?