How do you verify the identity #(sectheta-1)/(1-costheta)=sectheta#?

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Answer 1 · 2017-01-17T20:27:02

see below

Left Hand Side:

#(sec theta -1)/(1-cos theta) =( 1/cos theta -1)/(1-cos theta#

#=((1-costheta)/costheta)/(1-costheta)#

#=(1-costheta)/costheta*1/(1-costheta)#

#=cancel(1-costheta)/costheta*1/cancel(1-costheta)#

#=1/cos theta#

#=sec theta#

#:.=# Right Hand Side