How do you verify the identity (csc^2theta+2csctheta-3)/(csc^2theta-1)=(csctheta+3)/(csctheta+1)?

1 Answer
Aug 8, 2016

LHS=RHS

Explanation:

LHS
=(csc^2 theta+2csc theta-3)/(csc^2 theta-1)
=(csc^2 theta-csc theta+3csc theta-3)/((csc theta-1)(csc theta+1))
=(csc theta(csc theta-1)+3(csc theta-1))/((csc theta-1)(csc theta+1)
=(cancel((csctheta-1))(csc theta+3))/((cancel(csc theta-1))(csc theta+1)
=(csc theta+3)/(csc theta+1
Hence
LHS=RHS