How do you verify $tan^2x-tan^2x*sin^2x=sin^2x$ ?

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How do you verify $tan^2x-tan^2x*sin^2x=sin^2x$ ?

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Answer 1 · 2018-04-08T07:44:04

Please see below.

Explanation:

$tan^2x-tan^2x*sin^2x$

= $tan^2x(1-sin^2x)$

= $tan^2xcos^2x$

= $sin^2x/cos^2x*cos^2x$

= $sin^2x$

Answer 2 · 2018-04-08T08:04:16

$"see explanation"$

Explanation:

$"using the "color(blue)"trigonometric identities"$

$•color(white)(x)tanx=sinx/cosx$

$•color(white)(x)sin^2x+cos^2x=1$

$"consider the left side"$

$"take out a common factor "tan^2x$

$tan^2x(1-sin^2x)$

$=sin^2x/cancel(cos^2x)xxcancel(cos^2x)$

$=sin^2x=" right side "rArr"verified"$

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How do you verify $tan^2x-tan^2x*sin^2x=sin^2x$ ?

2 Answers

Explanation:

Explanation:

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