How do you verify #(tan^2)(sin^2)=tan^2+cos^2 - 1#?

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Answer 1 · 2016-03-07T16:12:50

Starting from the right hand side:

#tan^2(x)+cos^2(x)-1=#

#= tan^2(x)+cos^2(x)-sin^2(x)-cos^2(x)#

#=tan^2(x)-sin^2(x)#

#=sin^2(x)(sec^2(x)-1)#

#=sin^2(x)tan^2(x)#

#=tan^2(x)sin^2(x)#