How do you verify $(tan^2)(sin^2)=tan^2+cos^2 - 1$ ?

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Answer 1 · 2016-03-07T16:12:50

Starting from the right hand side:

$tan^2(x)+cos^2(x)-1=$

$= tan^2(x)+cos^2(x)-sin^2(x)-cos^2(x)$

$=tan^2(x)-sin^2(x)$

$=sin^2(x)(sec^2(x)-1)$

$=sin^2(x)tan^2(x)$

$=tan^2(x)sin^2(x)$

How do you verify (tan^2)(sin^2)=tan^2+cos^2 - 1(tan^2)(sin^2)=tan^2+cos^2 - 1?