How do you use transformation to graph the sin function and determine the amplitude and period of #y=sinx-6#?

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Answer 1 · 2017-10-30T15:10:50

Amplitude = 1 and Period = #2pi#

Standard form of equation is
#y=sin (bx +c) + d#

Where amplitude = a, Period = -(2pi)/b, phase shift = -c/b.

Given equation is #y=sin(x) - 6#

#a = 1, b = 1, c = 0, d = -6#

Therefore, #amplitude = a = 1#

#Period = (2pi)/b = (2pi)/1 = 2pi#

Phase shift = #-c/b = 0#

Vertical shift #= d = - 6#