How do you use the amplitude and period to graph #y=cos(x°+45°)-1#?

Question

1792 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-21T09:37:26

Amplitude is #1# and period is #2pi#.

In a typical sine or cosine function #y=alphacos(betax+gamma)+delta#,

#alpha# denotes amplitude,

period is #(2pi)/beta# or #360^o/beta#

phase shift is given by #(-gamma)/beta#

and #delta# denotes vertical shift.

Hence in #cos(x^o+45^o) -1#

Amplitude is #1# and period is #2pi#.

graph{cos(x+pi/4) -1 [-10, 10, -5, 5]}