How do you use the amplitude and period to graph $y= 2sin 3(x+30') + 4$ ?

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Answer 1 · 2018-06-23T02:39:42

$color(purple)(Amplitude = 2, "Period " = (2pi)/3$

$y = A sin (Bx - C) + D$ is the standard form

$"Given : " y = 2 sin (3x + 3* 30') + 4$

$90' = 1.5^@ = (1.5 * pi) / 180 = 0.0262^c$

$y = 2 sin(3x + 0.0262) + 4$

$A = 2, B = 3, C = -0.0262, D = 4$

$Amplitude = |A| = 2$

$"Period " = (2pi) / |B| = (2pi) / 3$

$"Phase Shift " = C / B = -0.0262/3 = -0.00873$

$"Vertical Shift " = D = 4$

graph{2 sin (3x -0.00873) + 4 [-10, 10, -5, 5]}

How do you use the amplitude and period to graph y= 2sin 3(x+30') + 4y= 2sin 3(x+30') + 4?