How do you solve $x(x+2)+3=0$ by completing the square?

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How do you solve $x(x+2)+3=0$ by completing the square?

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Answer 1 · 2015-05-10T09:24:21

$0 = x(x+2)+3 = x^2 + 2x + 3 = (x+1)^2+2$ . Subtracting 2 from both sides, we get $(x+1)^2 = -2$ . If you square any real number you will get a positive value, so there are no real solutions to the problem.

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How do you solve $x(x+2)+3=0$ by completing the square?

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How do you solve x(x+2)+3=0x(x+2)+3=0 by completing the square?

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How do you solve $x(x+2)+3=0$ by completing the square?