How do you solve $x^2-7x+5=0$ by completing the square?

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Answer 1 · 2016-08-07T04:14:22

$x=(7+-sqrt29)/2$

$x^2-7x+5=0$

$=>x^2-2*x*7/2+(7/2)^2-(7/2)^2+5=0$

$=>(x-7/2)^2=49/4-5=29/4$

$=>(x-7/2)=+-sqrt29/2$

$=>x=(7+-sqrt29)/2$

How do you solve x^2-7x+5=0x^2-7x+5=0 by completing the square?