How do you solve $x^{2} - 6 x = 16$ $x^2 - 6x = 16$ by completing the square?

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How do you solve $x^{2} - 6 x = 16$ $x^2 - 6x = 16$ by completing the square?

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Answer 1 · 2017-09-03T10:07:54

$x = - 2 or x = 8$ $x=-2" or "x=8$

Explanation:

$to complete the square$ $"to complete the square"$

add ${(\frac{1}{2} coefficient of x-term)}^{2} to both sides$ $(1/2" coefficient of x-term")^2" to both sides"$

$that is add {(- \frac{6}{2})}^{2} = 9 to both sides$ $"that is add "(-6/2)^2=9" to both sides"$

$\Rightarrow x^{2} + 2 (- 3) x + 9 = 16 + 9$ $rArrx^2+2(-3)xcolor(red)(+9)=16color(red)(+9)$

$\Rightarrow {(x - 3)}^{2} = 25$ $rArr(x-3)^2=25$

$take the square root of both sides$ $color(blue)"take the square root of both sides"$

$x - 3 = \pm 5 \leftarrow note plus or minus$ $x-3=+-5larr" note plus or minus"$

$\Rightarrow x = 3 \pm 5$ $rArrx=3+-5$

$\Rightarrow x = 3 - 5 or x = 3 + 5$ $rArrx=3-5" or "x=3+5$

$\Rightarrow x = - 2 or x = 8$ $rArrx=-2" or "x=8$

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How do you solve $x^{2} - 6 x = 16$ $x^2 - 6x = 16$ by completing the square?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve x2−6x=16x^2 - 6x = 16 by completing the square?

1 Answer

Explanation:

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How do you solve $x^{2} - 6 x = 16$ $x^2 - 6x = 16$ by completing the square?