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How do you solve #x^2-56=(-x)# by factoring?

1 Answer

Oct 23, 2015

#x=-8#
or
#x=7#

Explanation:

#x^2-56 = (-x)#

#rArr x^2+x-56 = 0#

Factoring:
#rArr (x+8)(x-7) = 0#

Either
#color(white)("XXX")(x+8) = 0 rArr x=-8#
or
#color(white)("XXX")(x-7)=0 rArr x=7#

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