How do you solve the polynomial 10x^3-5x^2=0?

1 Answer
Nov 18, 2014

In order to solve the algebraic equation for the variable x we would begin by factoring out the common factor from the equation
10x^3 - 5x^2 = 0
The common factor between 10x^3 and 5x^2 is 5x^2

5x^2(2x -1) = 0

Next we would set each value of x equal to 0

5x^2 = 0 and (2x -1) = 0

5x^2 = 0 divide by 5 and square root each side
x^2 = 0/5
x= 0

(2x -1) = 0 add 1 and divide by 2 on each side
2x = 0 + 1
x = 1/2

x = {0 , 1/2}