How do you solve the polynomial $10 x^{3} - 5 x^{2} = 0$ $10x^3-5x^2=0$ ?

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How do you solve the polynomial $10 x^{3} - 5 x^{2} = 0$ $10x^3-5x^2=0$ ?

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Answer 1 · 2014-11-18T02:44:20

In order to solve the algebraic equation for the variable x we would begin by factoring out the common factor from the equation
$10 x^{3} - 5 x^{2} = 0$ $10x^3 - 5x^2 = 0$
The common factor between $10 x^{3}$ $10x^3$ and $5 x^{2}$ $5x^2$ is $5 x^{2}$ $5x^2$

$5 x^{2} (2 x - 1) = 0$ $5x^2(2x -1) = 0$

Next we would set each value of x equal to 0

$5 x^{2} = 0 and (2 x - 1) = 0$ $5x^2 = 0 and (2x -1) = 0$

$5 x^{2} = 0$ $5x^2 = 0$ divide by 5 and square root each side
$x^{2} = \frac{0}{5}$ $x^2 = 0/5$
$x = 0$ $x= 0$

$(2 x - 1) = 0$ $(2x -1) = 0$ add 1 and divide by 2 on each side
$2 x = 0 + 1$ $2x = 0 + 1$
$x = \frac{1}{2}$ $x = 1/2$

$x = {0, \frac{1}{2}}$ $x = {0 , 1/2}$

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How do you solve the polynomial $10 x^{3} - 5 x^{2} = 0$ $10x^3-5x^2=0$ ?

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How do you solve the polynomial 10x3−5x2=010x^3-5x^2=0?

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How do you solve the polynomial $10 x^{3} - 5 x^{2} = 0$ $10x^3-5x^2=0$ ?