How do you solve (2u+7)(3u-1)=0(2u+7)(3u−1)=0?
1 Answer
Apr 16, 2018
u=(-7)/2u=−72
u=1/3u=13
Explanation:
Given
(2u+7)(3u-1)=0(2u+7)(3u−1)=0
2u+7=02u+7=0
2u=-72u=−7
u=(-7)/2u=−72
(3u-1)(3u−1)
3u=13u=1
u=1/3u=13