How do you solve (2u+7)(3u−1)=0?
1 Answer
Apr 16, 2018
u=−72
u=13
Explanation:
Given
(2u+7)(3u−1)=0
2u+7=0
2u=−7
u=−72
(3u−1)
3u=1
u=13
u=−72
u=13
Given
(2u+7)(3u−1)=0
2u+7=0
2u=−7
u=−72
(3u−1)
3u=1
u=13