How do you solve $x^2+3x+2$ by completing the square?

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Answer 1 · 2015-05-17T19:57:19

The answer is $x=-1$ and $x=-2$

$x^2+4x+4-x-2=0 => (x+2)^2-(x+2)=0$

So you know one answer is $x=-2$

Now you can divide the polynomial by its factor $(x+2)$ and you have

$x+2 - 1 = 0 => x=-1$

How do you solve x^2+3x+2x^2+3x+2 by completing the square?