How do you solve $x^2-2x+6=0$ by completing the square?

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How do you solve $x^2-2x+6=0$ by completing the square?

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Answer 1 · 2015-05-10T14:41:58

Write it as:
$x^2-2x=-6$
Add and subtract $1$ ;
$x^2-2x+1-1=-6$
$x^2-2x+1=-6+1$
$(x-1)^2=-5$
So:
$x-1=+-sqrt(-5)$
$x=1+-isqrt(5)$
These are two Complex Solutions where $i=sqrt(-1)$

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How do you solve $x^2-2x+6=0$ by completing the square?

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How do you solve x^2-2x+6=0x^2-2x+6=0 by completing the square?

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How do you solve $x^2-2x+6=0$ by completing the square?