How do you solve $x^2-2x-5=0$ by completing the square?

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Answer 1 · 2015-06-30T04:22:56

Solve $x^2 - 2x - 5$

$x^2 - 2x = 5$
$x^2 - 2x + 1 = 5 + 1 = 6$
$(x +1)^2 = 6$
$(x + 1) = +- sqrt6$

$x = -1 +- sqrt6$

How do you solve x^2-2x-5=0x^2-2x-5=0 by completing the square?