How do you solve $x^{2} - 12 x + 36 = 25$ $x^2 - 12x + 36 = 25$ by completing the square?

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Answer 1 · 2018-03-23T14:31:04

$x^{2} - 12 x + 36 = 25$ $x^2 -12x+36=25$

or, $x^{2} - 2 \cdot 6 \cdot x + {(6)}^{2} = 25$ $x^2 -2*6*x +(6)^2 =25$

or, ${(x - 6)}^{2} = 5^{2}$ $(x-6)^2 =5^2$

either, $x - 6 = 5$ $x-6=5$ or, $x - 6 = - 5$ $x-6=-5$

so, $x = 11$ $x=11$ or, $x = 1$ $x=1$

How do you solve x2−12x+36=25x^2 - 12x + 36 = 25 by completing the square?