How do you solve w224w2+136=0 by completing the square?

1 Answer
Jul 18, 2016

The solutions will be w=6±4i.

Explanation:

We can start by removing fractions from the mix by multiplying both sides by 24:
w212w+52=0

Now observing that we need an equation looking like w+b where 2b=12 it is clear that the squared term will be w6.

Since (w6)2=w212w+36 we can take 36 out of 52, this gives us:
(w6)2+16=0

we can manipulate this:
(w6)2=16

And take the square root of both sides:
w6=±4i
w=6±4i

You can check this answer by inputting the coefficients into the quadratic equation as well.