How do you solve #v-(-4)>6-3#?

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Answer 1 · 2017-05-16T12:26:43

#v> -1#

#v --4) > 6-3#

First, the #v-(-4)# bit means you're subtracting a negative number, which equals a positive value.

So, #v+4 > 6-3#

#6-3# is 3, so it is now:

#v+4>3#

To isolate v, you have to subtract #4# from BOTH sides.

#v> -1#.

This means that #v# can be any value as long as it is above #-1# (Excluding #-1#)