# How do you solve for x in #4-6x \le 2(2x+3)#?

##### 1 Answer

To solve an inequality of the first order (this is one because there isn't a higher exponent of x, than 1), you have to first bring every factor of x to one part, and every number to the other part.

This is your answer, you can flip it if that seams easier:

The set of solutions is all the numbers that are greater than or equal to

Hope this helped.

*(1): If you were to divide by a negative number, you would have to flip the inequality sign. In this case, #<=# would become #>=#*