How do you solve using the completing the square method $x(x - 2) = 5$ ?

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How do you solve using the completing the square method $x(x - 2) = 5$ ?

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Answer 1 · 2016-06-05T00:54:22

$x_1=1+sqrt6$

$x_2=1-sqrt6$

Explanation:

We start from the given equation

$x(x-2)=5$

Expand it to make it a trinomial

$x^2-2x=5$

We add 1 to both sides of the equation. The number $1$ is derived from numerical coefficient of x which is $-2$ . Divide -2 by 2 then square the result which is 1.

$x^2-2x+1=5+1$

$(x-1)^2=6$

Take the square root of both sides of the equation

$sqrt((x-1)^2)=+-sqrt6$

$x-1=+-sqrt6$

$x=+1+-sqrt6$

$x_1=1+sqrt6$

$x_2=1-sqrt6$

God bless....I hope the explanation is useful.

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How do you solve using the completing the square method $x(x - 2) = 5$ ?

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Science

Math

Humanities

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How do you solve using the completing the square method x(x - 2) = 5 x(x - 2) = 5?

1 Answer

Explanation:

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Impact of this question

How do you solve using the completing the square method $x(x - 2) = 5$ ?