How do you solve using the completing the square method $x^{2} - 8 x + 15 = 0$ $x^2-8x+15=0$ ?

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How do you solve using the completing the square method $x^{2} - 8 x + 15 = 0$ $x^2-8x+15=0$ ?

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Answer 1 · 2016-03-07T01:58:53

$x^{2} - 8 x = - 15 \to x^{2} - 8 x + {(- 4)}^{2} = - 15 + 16 \to {(x - 4)}^{2} = 1 \to x - 4 = \pm 1 \to x = 5 or x = 3$ $x^2-8x = -15 ->x^2-8x+(-4)^2=-15+16 ->(x-4)^2=1->x-4=+-1->x=5 or x=3$

Explanation:

First subtract the constant 15 over to the other side. Then half the middle term, square it and add to both sides. Take the square root of both sides and solve for x.

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How do you solve using the completing the square method $x^{2} - 8 x + 15 = 0$ $x^2-8x+15=0$ ?

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