How do you solve using the completing the square method $x^2 + 8x + 13 =0$ ?

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Answer 1 · 2016-07-27T04:39:28

$-4 +- sqrt3$

$x^2 + 8x + 13 = 0$
$x^2 + 8x = - 13$
$x^2 + 8x + 16 = -13 + 16 = 3$
$(x + 4)^2 = 3$
$(x + 4) = +- sqrt3$
$x = - 4 +- sqrt3$

How do you solve using the completing the square method x^2 + 8x + 13 =0x^2 + 8x + 13 =0?