How do you solve using the completing the square method $x^2 + 8x = 0$ ?

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Answer 1 · 2018-04-30T07:00:52

$x=4 or -8$

$x^2+8x=0$
you half the coefficient of $x$ and the take away this number squared.

$=>$ $(x+4)^2-16=0$

so the 8 becomes 4 and $4^2=16$

$=> (x+4)^2=16$

$=> x+4=\pm4$

$=>x+4=4$ or $x+4=-4$

$=> x=0 or x=-8$

How do you solve using the completing the square method x^2 + 8x = 0x^2 + 8x = 0?