How do you solve using the completing the square method $x^{2} - 6 x = 27$ $x^2-6x=27$ ?

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How do you solve using the completing the square method $x^{2} - 6 x = 27$ $x^2-6x=27$ ?

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Answer 1 · 2016-07-30T08:46:39

$x = 9$ $x=9$
$x = - 3$ $x=-3$

Explanation:

$x^{2} - 6 x = 27$ $x^2-6x=27$
or
$x^{2} - 6 x + 9 = 27 + 9$ $x^2-6x+9=27+9$
or
$x^{2} - 2 x (3) + 3^{2} = 36$ $x^2-2x(3)+3^2=36$
or
${(x - 3)}^{2} = 6^{2}$ $(x-3)^2=6^2$
or
$x - 3 = \pm 6$ $x-3=+-6$
or
$x = 3 + 6 = 9$ $x=3+6=9$
or
$x = 3 - 6 = - 3$ $x=3-6=-3$

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How do you solve using the completing the square method $x^{2} - 6 x = 27$ $x^2-6x=27$ ?

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Science

Math

Humanities

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How do you solve using the completing the square method x2−6x=27x^2-6x=27 ?

1 Answer

Explanation:

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How do you solve using the completing the square method $x^{2} - 6 x = 27$ $x^2-6x=27$ ?