How do you solve using the completing the square method $x^{2} + 6 x + 1 = 0$ $x^2+6x+1=0$ ?

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How do you solve using the completing the square method $x^{2} + 6 x + 1 = 0$ $x^2+6x+1=0$ ?

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Answer 1 · 2016-03-14T17:25:00

$x = - 3 \pm 2 \sqrt{2}$ $x = -3 +- 2sqrt2$

Explanation:

$x^{2} + 6 x = - 1$ $x^2 + 6x = -1$
$x^{2} + 6 x + 9 = - 1 + 9 = 8$ $x^2 + 6x + 9 = -1 + 9 = 8$
${(x + 3)}^{2} = 8$ $(x + 3)^2 = 8$
$(x + 3) = \sqrt{8} = 2 \sqrt{2}$ $(x + 3) = sqrt8 = 2sqrt2$
$x = - 3 \pm 2 \sqrt{2}$ $x = - 3 +- 2sqrt2$

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How do you solve using the completing the square method $x^{2} + 6 x + 1 = 0$ $x^2+6x+1=0$ ?

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Math

Humanities

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How do you solve using the completing the square method x2+6x+1=0x^2+6x+1=0?

1 Answer

Explanation:

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How do you solve using the completing the square method $x^{2} + 6 x + 1 = 0$ $x^2+6x+1=0$ ?