How do you solve using the completing the square method $x^{2} + 4 x + 2 = 0$ $x^2 + 4x + 2 = 0$ ?

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Answer 1 · 2017-03-23T23:46:13

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$x^{2} + 4 x + 2 = 0$ $x^2 + 4x + 2 = 0$

${(x + 2)}^{2} - 4 + 2 = 0$ $(x + 2)^2 - 4 + 2 = 0$

${(x + 2)}^{2} - 2 = 0$ $(x + 2)^2 - 2 = 0$

${(x + 2)}^{2} = 2$ $(x + 2)^2 = 2$

$x + 2 = \pm \sqrt{2}$ $x + 2 =pm sqrt2$

$x = \pm \sqrt{2} - 2$ $x =pm sqrt2 - 2$

How do you solve using the completing the square method x2+4x+2=0x^2 + 4x + 2 = 0?