How do you solve using the completing the square method $x^2 - 4x =12$ ?

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Answer 1 · 2018-04-10T21:13:55

$y=(x-2)^2-16$

First set the equation equal to 0

$x^2-4x-12=0$

Now complete the square

$[x^2-4x]-12$
$[(x-2)^2-4]-12$
$(x-2)^2-4-12$
$(x-2)^2-16$

How do you solve using the completing the square method x^2 - 4x =12 x^2 - 4x =12 ?