How do you solve using the completing the square method $x^2-4x=10$ ?

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Answer 1 · 2016-03-21T19:56:57

You take half of the number that's with the single $x$ , and add the square of that to both sides.

$->x^2+2*(-2)x+(-2)^2=10+(-2)^2$

Or, after 'cleaning up':
$->(x-2)^2=14$

Then take the square root on both sides (do not forget the negative answer):
$->x-2=+-sqrt14->x=2+sqrt14orx=2-sqrt14$

How do you solve using the completing the square method x^2-4x=10 x^2-4x=10?