How do you solve using the completing the square method $x^2-3/2x-23/16=0$ ?

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How do you solve using the completing the square method $x^2-3/2x-23/16=0$ ?

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Answer 1 · 2016-03-14T16:32:54

$x = 3/4 +- sqrt59/4$

Explanation:

$x^2 - (3x)/2 - 23/26$ .
$x^2 - (3x)/2 = 12/16$
$x^2 - (3x)/2 + 9/4 = 12/16 + 9/4$
$(x - 3/4)^2 = 59/16$
$(x - 3/4) = +- sqrt59/4$
$x = 3/4 +- sqrt59/4$

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How do you solve using the completing the square method $x^2-3/2x-23/16=0$ ?

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How do you solve using the completing the square method x^2-3/2x-23/16=0x^2-3/2x-23/16=0?

1 Answer

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How do you solve using the completing the square method $x^2-3/2x-23/16=0$ ?