How do you solve using the completing the square method $x^{2} + 2 x = 7$ $x^2 + 2x = 7$ ?

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How do you solve using the completing the square method $x^{2} + 2 x = 7$ $x^2 + 2x = 7$ ?

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Answer 1 · 2016-08-10T14:11:35

$x = - 1 \pm 2 \sqrt{2}$ $x = - 1 +- 2sqrt2$

Explanation:

$x^{2} + 2 x = 7$ $x^2 + 2x = 7$
$x^{2} + 2 x + 1 = 7 + 1$ $x^2 + 2x + 1 = 7 + 1$
${(x + 1)}^{2} = 8$ $(x + 1)^2 = 8$
$x + 1 = \pm 2 \sqrt{2}$ $x + 1 = +- 2sqrt2$
$x = - 1 \pm 2 \sqrt{2}$ $x = - 1 +- 2sqrt2$

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How do you solve using the completing the square method $x^{2} + 2 x = 7$ $x^2 + 2x = 7$ ?

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Explanation:

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Science

Math

Humanities

... and beyond

How do you solve using the completing the square method x2+2x=7x^2 + 2x = 7?

1 Answer

Explanation:

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Impact of this question

How do you solve using the completing the square method $x^{2} + 2 x = 7$ $x^2 + 2x = 7$ ?