How do you solve using the completing the square method $x^{2} - 2 x - 4 = 0$ $x^2-2x-4=0$ ?

Question

How do you solve using the completing the square method $x^{2} - 2 x - 4 = 0$ $x^2-2x-4=0$ ?

1 Answer

Impact of this question

1638 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-19T12:45:57

$x = 1 \pm \sqrt{5}$ $x = 1 +- sqrt5$

Explanation:

$x^{2} - 2 x = 4$ $x^2 - 2x = 4$
$x^{2} - 2 x + 1 = 4 + 1$ $x^2 - 2x + 1 = 4 + 1$
${(x - 1)}^{2} = 5$ $(x - 1)^2 = 5$
$(x - 1) = \pm \sqrt{5}$ $(x - 1) = +- sqrt5$
$x = 1 \pm \sqrt{5}$ $x = 1 +- sqrt5$

Science

Math

Humanities

... and beyond

How do you solve using the completing the square method $x^{2} - 2 x - 4 = 0$ $x^2-2x-4=0$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve using the completing the square method x2−2x−4=0x^2-2x-4=0?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve using the completing the square method $x^{2} - 2 x - 4 = 0$ $x^2-2x-4=0$ ?