How do you solve using the completing the square method $x^{2} - 2 x - 3 = 0$ $x^2 - 2x -3 = 0$ ?

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How do you solve using the completing the square method $x^{2} - 2 x - 3 = 0$ $x^2 - 2x -3 = 0$ ?

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Answer 1 · 2018-03-05T00:06:51

$x = 3$ $x = 3" "$ or $x = - 1$ $" "x = -1$

Explanation:

$0 = x^{2} - 2 x - 3$ $0 = x^2-2x-3$

$0 = x^{2} - 2 x + 1 - 4$ $color(white)(0) = x^2-2x+1-4$

$0 = {(x - 1)}^{2} - 2^{2}$ $color(white)(0) = (x-1)^2-2^2$

$0 = ((x - 1) - 2) ((x - 1) + 2)$ $color(white)(0) = ((x-1)-2)((x-1)+2)$

$0 = (x - 3) (x + 1)$ $color(white)(0) = (x-3)(x+1)$

Hence:

$x = 3$ $x = 3" "$ or $x = - 1$ $" "x = -1$

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How do you solve using the completing the square method $x^{2} - 2 x - 3 = 0$ $x^2 - 2x -3 = 0$ ?

1 Answer

Explanation:

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How do you solve using the completing the square method $x^{2} - 2 x - 3 = 0$ $x^2 - 2x -3 = 0$ ?