How do you solve using the completing the square method $x^2-2x-13 = 0$ ?

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How do you solve using the completing the square method $x^2-2x-13 = 0$ ?

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Answer 1 · 2018-01-09T09:50:21

$x=1+-sqrt14$

Explanation:

$• " the coefficient of the "x^2" term must be 1 which it is"$

$• " add "(1/2"coefficient of x-term")^2" to both sides"$

$x^2-2x-13=0$

$rArrx^2-2x=13$

$rArrx^2+2(-1)xcolor(red)(+1)=13color(red)(+1)$

$rArr(x-1)^2=14$

$color(blue)"take the square root of both sides"$

$x-1=+-sqrt14larrcolor(blue)"note plus or minus"$

$rArrx=1+-sqrt14$

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How do you solve using the completing the square method $x^2-2x-13 = 0$ ?

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How do you solve using the completing the square method x^2-2x-13 = 0x^2-2x-13 = 0?

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How do you solve using the completing the square method $x^2-2x-13 = 0$ ?