How do you solve using the completing the square method $x^2-14x+5=0$ ?

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Answer 1 · 2016-04-03T01:33:10

$x = 7+-2sqrt(11)$

$x^2-14x+5 = 0$

$=> x^2-14x = -5$

$=> x^2 - 14x + 49 = -5+49$

$=> x^2-14x+49 = 44$

$=> (x-7)^2 = 44$

$=> x-7 = +-sqrt(44) = +-2sqrt(11)$

$:. x = 7+-2sqrt(11)$

How do you solve using the completing the square method x^2-14x+5=0 x^2-14x+5=0 ?