How do you solve using the completing the square method $x^{2} - 12 x + 20 = 0$ $x^2-12x+20=0$ ?

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How do you solve using the completing the square method $x^{2} - 12 x + 20 = 0$ $x^2-12x+20=0$ ?

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Answer 1 · 2018-05-29T19:48:09

$x = 2 or x = 10$ $x=2" or "x=10$

Explanation:

$subtract 20 from both sides$ $"subtract 20 from both sides"$

$x^{2} - 12 x = - 20$ $x^2-12x=-20$

$∙ add {(\frac{1}{2} coefficient of the x-term)}^{2} to both sides$ $• " add "(1/2"coefficient of the x-term")^2" to both sides"$

$x^{2} + 2 (- 6) x + 36 = - 20 + 36$ $x^2+2(-6)x color(red)(+36)=-20color(red)(+36)$

${(x - 6)}^{2} = 16$ $(x-6)^2=16$

$take the square root of both sides$ $color(blue)"take the square root of both sides"$

$\sqrt{{(x - 6)}^{2}} = \pm \sqrt{16} \leftarrow note plus or minus$ $sqrt((x-6)^2)=+-sqrt16larrcolor(blue)"note plus or minus"$

$x - 6 = \pm 4$ $x-6=+-4$

$add 6 to both sides$ $"add 6 to both sides"$

$x = 6 \pm 4$ $x=6+-4$

$x = 6 - 4 = 2 or x = 6 + 4 = 10$ $x=6-4=2" or "x=6+4=10$

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How do you solve using the completing the square method $x^{2} - 12 x + 20 = 0$ $x^2-12x+20=0$ ?

1 Answer

Explanation:

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How do you solve using the completing the square method x^2-12x+20=0x2−12x+20=0x^2-12x+20=0?

1 Answer

Explanation:

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How do you solve using the completing the square method $x^{2} - 12 x + 20 = 0$ $x^2-12x+20=0$ ?