How do you solve using the completing the square method $x^2 + 10x + 16 = 0$ ?

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How do you solve using the completing the square method $x^2 + 10x + 16 = 0$ ?

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Answer 1 · 2016-02-26T09:51:10

$x=-2$ and $x=-8$

Explanation:

To solve the equation $x^2+10x+16=0$ using the completing square method, as coefficient of $x^2$ is $1$ and independent term $16$ positive, we have to identify factors of $16$ whose sum is $10$ , coefficient of $x$ term.

These are $2$ and $8$ and hence we should split the equation as follows:

$x^2+2x+8x+16=0$ or $x(x+2)+8(x+2)=0$ i.e.

$(x+2)(x+8)=0$ .

Hence either $x+2=0$ i.e. $x=-2$ or

$x+8=0$ i.e. $x=-8$

[In general if equation is in form $ax^2+bx+c=0$ , one should identify two factors whose product is $a*c$ and sum is $b$ .]

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How do you solve using the completing the square method $x^2 + 10x + 16 = 0$ ?

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How do you solve using the completing the square method x^2 + 10x + 16 = 0x^2 + 10x + 16 = 0?

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How do you solve using the completing the square method $x^2 + 10x + 16 = 0$ ?