How do you solve using the completing the square method 3x^2 + 2x + 5 = 0?

1 Answer
Binayaka C.
Feb 14, 2017

Solution: x =-1/3 +sqrt (14)/3* i or x =-1/3 - sqrt (14)/3* i

Explanation:

3x^2+2x+5 =0 or 3(x^2+2/3x) +5 =0 or 3(x^2+2/3x+(1/3)^2) -1/3+5 =0 or 3( x+1/3)^2 +14/3 =0 or ( x+1/3)^2 = -14/9 or x +1/3 = +-sqrt (-14/9)
or x = -1/3 +- sqrt (-14/9) :. x =-1/3 +sqrt (14)/3* i or x =-1/3 - sqrt (14)/3* i [i^2 = -1]
Solution: x =-1/3 +sqrt (14)/3* i or x =-1/3 - sqrt (14)/3* i [Ans]

Related questions
See all questions in Completing the Square
Impact of this question
3687 views around the world
You can reuse this answer
Creative Commons License