How do you solve using the completing the square method $3 x^{2} + 14 x = 5$ $3x^2+14x=5$ ?

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Answer 1 · 2018-06-14T15:01:31

$x = \frac{1}{3}, - 5$ $color(crimson)(x = 1/3, -5$

$3 x^{2} + 14 x = 5$ $3x^2 + 14x = 5$

$3 x^{2} + 14 x + \frac{49}{3} = 5 + \frac{49}{3}$ $3x^2 + 14x + 49/3 = 5 + 49/3$

${(\sqrt{3} x + \frac{7}{\sqrt{3}})}^{2} = {(\frac{8}{\sqrt{3}})}^{2}$ $(sqrt3 x + 7/sqrt3)^2 = (8/sqrt3)^2$

$\sqrt{3} x + \frac{7}{\sqrt{3}} = \pm \frac{8}{\sqrt{3}}$ $sqrt3 x + 7/sqrt3 = +- 8 / sqrt3$

$\sqrt{3} x = \pm \frac{8}{\sqrt{3}} - \frac{7}{\sqrt{3}}$ $sqrt3 x = +- 8/sqrt3 - 7/sqrt3$

$x = (\frac{1}{3}) (- 7 \pm 8)$ $x = (1/3) (-7 +- 8)$

$x = \frac{1}{3}, - 5$ $color(crimson)(x = 1/3, -5$

How do you solve using the completing the square method 3x2+14x=53x^2+14x=5?