How do you solve using completing the square method $m^2+4m+2=0$ ?

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How do you solve using completing the square method $m^2+4m+2=0$ ?

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Answer 1 · 2016-10-05T06:24:02

$m = -2+-sqrt(2)$

Explanation:

The difference of squares identity can be written:

$a^2-b^2 = (a-b)(a+b)$

Use this with $a=(m+2)$ and $b=sqrt(2)$ as follows:

$0 = m^2+4m+2$

$color(white)(0) = m^2+4m+4-2$

$color(white)(0) = (m+2)^2-(sqrt(2))^2$

$color(white)(0) = ((m+2)-sqrt(2))((m+2)+sqrt(2))$

$color(white)(0) = (m+2-sqrt(2))(m+2+sqrt(2))$

Hence:

$m = -2+-sqrt(2)$

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How do you solve using completing the square method $m^2+4m+2=0$ ?

1 Answer

Explanation:

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How do you solve using completing the square method m^2+4m+2=0m^2+4m+2=0?

1 Answer

Explanation:

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How do you solve using completing the square method $m^2+4m+2=0$ ?