How do you solve using completing the square method $(-2/3)x^2 + (-4/3)x + 1 = 0$ ?

Question

How do you solve using completing the square method $(-2/3)x^2 + (-4/3)x + 1 = 0$ ?

1 Answer

Impact of this question

1301 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-06T05:32:15

$x=-1+sqrt(5/2)$ or $-1-sqrt(5/2)$

Explanation:

We have $(-2/3)x^2+(-4/3)x+1=0$

As $(-2/3)x^2$ is not a complete square, let us multiply each term by $-3/2$ , so that we get $x^2$ , which is a complete square. Then our equation becomes

$(-2/3)xx(-3/2)x^2+(-4/3)xx(-3/2)x-3/2=0$

or $x^2+2x-3/2=0$

or $(x^2+2x+1)-1-3/2=0$

or $(x+1)^2-5/2=0$

or $(x+1)^2-(sqrt(5/2))^2=0$

i.e. $(x+1-sqrt(5/2))(x+1+sqrt(5/2))=0$

Hence, $x=-1+sqrt(5/2)$ or $-1-sqrt(5/2)$

Science

Math

Humanities

... and beyond

How do you solve using completing the square method $(-2/3)x^2 + (-4/3)x + 1 = 0$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve using completing the square method (-2/3)x^2 + (-4/3)x + 1 = 0(-2/3)x^2 + (-4/3)x + 1 = 0?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve using completing the square method $(-2/3)x^2 + (-4/3)x + 1 = 0$ ?