How do you solve the quadratic equation by completing the square: $X^2 + 3x – 1 = 0$ ?

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Answer 1 · 2015-07-18T01:10:21

Solve y = x^2 + 3x - 1 = 0
$x = -3/2 +- (sqrt13)/2$

$x^2 + 3x + 9/4 = 1 + 9/4 = 13/4$
$(x + 3/2)^2 = 13/4$
$(x + 3/2) = +- (sqrt13)/2$

$x = -3/2 +- (sqrt13)/2$

How do you solve the quadratic equation by completing the square: X^2 + 3x – 1 = 0X^2 + 3x – 1 = 0?