How do you solve the quadratic equation by completing the square: $x^{2} + 10 x - 2 = 0$ $x^2+10x-2=0$ ?

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Answer 1 · 2015-08-09T18:24:18

$x = - 5 \pm 3 \sqrt{3}$ $x=-5+-3sqrt(3)$

Tranform the equation to this form
$x^{2} + 10 - 2 = {(x + 5)}^{2} - 27 = 0$ $x^2+10-2=(x+5)^2-27=0$

Then rearrange to make $x$ $x$ the subject:
$x + 5 = \pm \sqrt{27} = \pm 3 \sqrt{3}$ $x+5=+-sqrt(27)=+-3sqrt(3)$

=>

$x = - 5 \pm 3 \sqrt{3}$ $x=-5+-3sqrt(3)$

How do you solve the quadratic equation by completing the square: x2+10x−2=0x^2+10x-2=0?