How do you solve the quadratic equation by completing the square: ${(2 x - 3)}^{2} = 8$ $(2x-3)^2=8$ ?

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How do you solve the quadratic equation by completing the square: ${(2 x - 3)}^{2} = 8$ $(2x-3)^2=8$ ?

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Answer 1 · 2015-07-22T00:04:27

I think you already completed the square (on the left)!!!

Explanation:

You can take the square root of both sides:
$2 x - 3 = \pm \sqrt{8}$ $2x-3=+-sqrt(8)$
so you get two solutions; rearranging:
$x_{1} = \frac{3 + \sqrt{8}}{2}$ $x_1=(3+sqrt(8))/2$
$x_{2} = \frac{3 - \sqrt{8}}{2}$ $x_2=(3-sqrt(8))/2$

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How do you solve the quadratic equation by completing the square: ${(2 x - 3)}^{2} = 8$ $(2x-3)^2=8$ ?

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How do you solve the quadratic equation by completing the square: (2x−3)2=8(2x-3)^2=8?

1 Answer

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How do you solve the quadratic equation by completing the square: ${(2 x - 3)}^{2} = 8$ $(2x-3)^2=8$ ?