How do you solve the equation $x^2-3x-7=0$ by completing the square?

Question

7371 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-03T08:01:50

$color(blue)(x = 4.54, -1.54$

$x^2 - 3x - 7 = 0$

$x^2 - (2*(3/2)*x) = 7$

Adding $(3/2)^2$ to both sides,

$x^2 - (2 * 3/2) * x) + (3/2)^2 = 7 + (3/2)^2 = 37/4$

$(x - (3/2))^2 = (sqrt(37/4))^2$

$x =+- sqrt(37/4)+ (3/2)$

$color(blue)(x= 4.54, -1.54$

How do you solve the equation x^2-3x-7=0x^2-3x-7=0 by completing the square?