How do you solve the equation $x^2-16x=-20$ by completing the square?

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Answer 1 · 2017-06-04T15:28:48

$x=8+-2sqrt11$

$x^2-16x=-20$

$x^2-16x+8^2-8^2=-20$

$(x-8)^2-64=-20$

$(x-8)^2=44$

$x-8=+-sqrt44=+-2sqrt11$

$x=8+-2sqrt11$

How do you solve the equation x^2-16x=-20x^2-16x=-20 by completing the square?