How do you solve by completing the square $x^{2} + 6 x + 2 = 0$ $x^2+6x+2=0$ ?

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Answer 1 · 2015-03-30T10:17:04

The answer is:

$x^{2} + 6 x + 9 - 9 + 2 = 0 \Rightarrow {(x + 3)}^{2} = 7 \Rightarrow$ $x^2+6x+9-9+2=0rArr(x+3)^2=7rArr$

$x + 3 = \pm \sqrt{7} \Rightarrow x = - 3 \pm \sqrt{7}$ $x+3=+-sqrt7rArrx=-3+-sqrt7$ .

How do you solve by completing the square x2+6x+2=0x^2+6x+2=0?