How do you solve by completing the square: $x^2 - 14x = 51$ ?

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Answer 1 · 2015-03-30T18:23:00

This is the way:

$x^2-14x=51rArrx^2-14x+7^2-7^2=51rArr$

$x^2-14x+49=51+49rArr(x-7)^2=100rArr$

$x-7=+-10rArrx=7+-10rArr$

$x_1=7-10=-3$

$x_2=7+10=17$ .

How do you solve by completing the square: x^2 - 14x = 51x^2 - 14x = 51?