How do you solve by completing the square $9 x^{2} + 6 x = 8$ $9x^2+6x=8$ ?

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How do you solve by completing the square $9 x^{2} + 6 x = 8$ $9x^2+6x=8$ ?

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Answer 1 · 2015-04-01T13:18:21

I would try:
$x^{2} + \frac{6}{9} x = \frac{8}{9}$ $x^2+6/9x=8/9$
$x^{2} + \frac{2}{3} x = \frac{8}{9}$ $x^2+2/3x=8/9$
$x^{2} + \frac{2}{3} x + \frac{1}{9} - \frac{1}{9} = \frac{8}{9}$ $x^2+2/3x+1/9-1/9=8/9$
${(x + \frac{1}{3})}^{2} = \frac{8}{9} + \frac{1}{9}$ $(x+1/3)^2=8/9+1/9$
$x + \frac{1}{3} = \pm \sqrt{1}$ $x+1/3=+-sqrt(1)$
$x = - \frac{1}{3} \pm 1$ $x=-1/3+-1$
$x_{1} = \frac{2}{3}$ $x_1=2/3$
$x_{2} = - \frac{4}{3}$ $x_2=-4/3$

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How do you solve by completing the square $9 x^{2} + 6 x = 8$ $9x^2+6x=8$ ?

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How do you solve by completing the square $9 x^{2} + 6 x = 8$ $9x^2+6x=8$ ?